Question

a force of 30 n to the right is applied to an object. an opposite force of 20 n to the left is applied to the same object. what is the net force applied to the object? (1 point) 50 n to the right 50 n to the left 10 n to the left 10 n to the right

Explanation:

Step1: Define positive and negative directions

Let right - direction be positive ($+30\ N$) and left - direction be negative ($- 20\ N$).

Step2: Calculate net force

Net force $F_{net}=F_1 + F_2$. Substitute $F_1 = 30\ N$ and $F_2=-20\ N$ into the formula.
$F_{net}=30+( - 20)=30 - 20=10\ N$

Answer:

10 N to the right