Question

a football coach walks 18 meters westward, then 12 meters eastward, then 28 meters westward, and finally 14 meters eastward. for this motion, what is the distance moved? distance (m) = what is the magnitude and direction of the displacement? magnitude (m) = dirn =

Explanation:

Step1: Calculate the distance

Distance is the total path length.
$$18 + 12+28 + 14$$
$$=(18+12)+(28 + 14)$$
$$=30+42$$
$$=72$$

Step2: Calculate the displacement

Let westward be positive.
First movement: \(d_1 = 18\) m (west), second: \(d_2=- 12\) m (east), third: \(d_3 = 28\) m (west), fourth: \(d_4=-14\) m (east)
Displacement \(D=d_1 + d_2+d_3 + d_4\)
$$D=18-12 + 28-14$$
$$=(18 + 28)-(12 + 14)$$
$$=46-26$$
$$=20$$

Answer:

Distance \((m)=72\)
Magnitude \((m)=20\)
Dir'n = West