Question

following could be used to calculate the measure of ∠qro? m∠qpo+(x + 16)°+(6x - 4)° = 360° m∠qpo=(x + 16)°+(6x - 4)° m∠qpo+(2x + 16)°=180° m∠qpo=(6x - 4)°+(2x + 16)°

Explanation:

Step1: Recall cyclic - quadrilateral property

In a cyclic quadrilateral, opposite angles are supplementary, i.e., they add up to 180°. In cyclic quadrilateral \(PQRO\), \(\angle QRO\) and \(\angle QPO\) are opposite angles.

Step2: Identify the relationship

We know that \(m\angle QRO=(2x + 16)^{\circ}\) and \(\angle QRO\) and \(\angle QPO\) are opposite angles in the cyclic - quadrilateral. So, \(m\angle QPO+(2x + 16)^{\circ}=180^{\circ}\).

Answer:

C. \(m\angle QPO+(2x + 16)^{\circ}=180^{\circ}\)