Question

this flow chart shows the amount of energy that is emitted by each type of light. ultraviolet > blue light > yellow light > red light (maximum energy) (minimum energy) in an experiment, shining which type of light on a strip of metal would be least likely to produce the photoelectric effect? ultraviolet light dim blue light bright red light bright yellow light

Explanation:

The photoelectric effect occurs when light with sufficient energy strikes a metal. The energy of light is related to its frequency (higher - energy light has a higher frequency). As per the given energy order \(ultraviolet>blue\ light>yellow\ light>red\ light\) (minimum energy), red light has the least energy among the given options. Brightness (intensity) of light affects the number of electrons emitted (in case of sufficient - energy light) but not whether the photoelectric effect occurs. Since red light has the lowest energy, it is least likely to have energy equal to or greater than the work function (the minimum energy required to eject an electron from the metal) of the metal.

Answer:

C. bright red light