Question

1. in flies, long wings (w) are dominant to short wings (w). two homozygous recessive flies are crossed. homozygous recessive fly homozygous recessive fly phenotype probability (%) long wings: short wings:

Explanation:

Step1: Determine the genotypes of the parents

Since both parents are homozygous recessive, their genotypes are \(ww\).

Step2: Create a Punnett square

The Punnett square for \(ww\times ww\) is:

	\(w\)	\(w\)
\(w\)	\(ww\)	\(ww\)

Step3: Calculate the probabilities

All offspring have the genotype \(ww\). For phenotype, since \(w\) (short - wings) is recessive, and there is no \(W\) (dominant long - wings allele) in any of the offspring.

Answer:

Long Wings: \(0\%\)
Short Wings: \(100\%\)