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Question
a flashlight is projecting a triangle onto a wall, as shown below. the original triangle and its projection are similar. what is the missing length ( n ) on the projection? options: ( 16\frac{2}{3} ), ( 13\frac{1}{2} ), 23, 24
Step1: Set up proportion for similar triangles
Since the triangles are similar, the ratios of corresponding sides are equal. So, $\frac{15}{20}=\frac{18}{n}$ (Wait, no, correct corresponding sides: let's check the sides. The original triangle has sides 15, 16, 18? Wait, no, the projected triangle has sides 20, 20, n? Wait, maybe the corresponding sides are 15 and 20, 18 and n. Wait, let's re-express. Let the smaller triangle have sides 15, 18, 16? Wait, maybe the correct proportion is $\frac{15}{20}=\frac{18}{n}$? No, wait, maybe the sides are 15 (corresponding to 20), 18 (corresponding to n). Wait, similar triangles: corresponding sides are proportional. So if the first triangle has a side of length 15 and the second has 20, and another side of 18 in the first and n in the second, then $\frac{15}{20}=\frac{18}{n}$. Wait, no, maybe I mixed up. Wait, let's see the sides: the smaller triangle (original) has sides 15, 18, 16? Wait, the larger triangle (projection) has sides 20, 20, n? Wait, maybe the correct corresponding sides are 15 and 20, 18 and n. Wait, let's solve the proportion. Cross - multiply: $15n = 20\times18$.
Step2: Solve for n
First, calculate $20\times18 = 360$. Then, $n=\frac{360}{15}=24$? Wait, no, wait, maybe the corresponding sides are 15 and 20, 16 and 20? Wait, no, the angles are equal, so the sides opposite equal angles are proportional. Wait, maybe the correct proportion is $\frac{15}{20}=\frac{18}{n}$. Wait, let's check the numbers again. If the original triangle has a side of 15 and the projected has 20, and original has 18 and projected has n, then $\frac{15}{20}=\frac{18}{n}$. Cross - multiplying: $15n = 20\times18=360$. Then $n=\frac{360}{15}=24$. Wait, but let's check another way. If the original triangle has sides 15, 18, 16 (wait, maybe 15, 16, 18? No, the projected has two sides 20. Wait, maybe the triangle is isoceles? Wait, the original triangle: one side 15, one 16, one 18. The projected triangle: two sides 20, one n. Wait, maybe the corresponding sides are 15 and 20, 16 and 20? No, that can't be. Wait, maybe I made a mistake in corresponding sides. Let's look at the angles. The angles with the arcs are equal, so the sides opposite them are proportional. So in the original triangle, the side opposite the angle with one arc is 18, and in the projected triangle, the side opposite the same - angled angle is n. The side opposite the angle with two arcs: original is 15, projected is 20. So the ratio of similarity is $\frac{20}{15}=\frac{4}{3}$. Then, the side n should be $18\times\frac{4}{3}=24$. Yes, that makes sense. So the proportion is $\frac{15}{20}=\frac{18}{n}$ (wait, no, $\frac{15}{20}=\frac{3}{4}$, and $\frac{18}{n}=\frac{3}{4}$? No, wait, $\frac{20}{15}=\frac{4}{3}$, so $n = 18\times\frac{4}{3}=24$.
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