first, find m∠khl. m∠khl = \$\\square^\\circ\$ m∠khl = 180° − m∠jhk

$first, find m∠khl. m∠khl = \$\\square^\\circ\$ m∠khl = 180° − m∠jhk$

first, find m∠khl. m∠khl = \$\square^\circ\$ m∠khl = 180° − m∠jhk

Points J, H, L form a straight line, so $\angle JHL = 180^\circ$.

$\angle KHL = 180^\circ - \angle JHK = 180^\circ - 51^\circ = 129^\circ$

129