Question

finding a pre - image figure abcde was reflected across the line ( y = x ) to create figure ( abcde ). what are the coordinates of the pre - image of ( e )? ( e(square,square) )

Explanation:

Step1: Recall reflection rule

When reflecting a point $(x,y)$ across the line $y = x$, the rule is $(x,y)\to(y,x)$.

Step2: Locate $E'$ coordinates

From the graph, the coordinates of $E'$ are $(6,-2)$.

Step3: Apply inverse of reflection rule

Let the pre - image of $E'$ be $(a,b)$. Using the reflection rule $(a,b)\to(b,a)=(6,-2)$. So, $a=-2$ and $b = 6$.

Answer:

$(-2,6)$