QUESTION IMAGE
Question
find the values of x and y.
y - 10 = x
right triangle with right angle, angle x, angle y
x = box
y = box
Step1: Use the property of right - angled triangle
In a right - angled triangle, the sum of the two non - right angles is \(90^{\circ}\). So \(x + y=90\).
Step2: Substitute \(x=y - 10\) into \(x + y=90\)
Substitute \(x=y - 10\) into \(x + y=90\), we get \((y - 10)+y=90\).
Simplify the left - hand side: \(2y-10 = 90\).
Add \(10\) to both sides: \(2y=90 + 10=100\).
Divide both sides by \(2\): \(y=\frac{100}{2}=50\).
Step3: Find the value of \(x\)
Since \(x=y - 10\) and \(y = 50\), then \(x=50-10 = 40\).
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\(x = 40\), \(y = 50\)