Question

find the value of x.
round to the nearest tenth.

Explanation:

Step1: Apply Pythagorean theorem

$$a^{2}+b^{2}=c^{2}$$
Here \(a = 6\), \(b=10\), and \(c=x\).

Step2: Substitute values

$$6^{2}+10^{2}=x^{2}$$
$$36 + 100=x^{2}$$
$$x^{2}=136$$

Step3: Solve for \(x\)

$$x=\sqrt{136}\approx11.7$$

Answer:

\(11.7\)