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Question
- find the value of x that makes the triangles similar. show your work using proportions!
a.
b.
Step1: Apply the basic proportionality theorem (for part a)
If a line is parallel to one side of a triangle and intersects the other two sides, then it divides those sides proportionally. So, \(\frac{5}{15}=\frac{x}{12}\).
Step2: Solve the proportion for \(x\) (for part a)
Cross - multiply: \(15x = 5\times12\). Then \(15x=60\), and \(x=\frac{60}{15}=4\).
Step3: Apply the property of similar triangles (for part b)
For similar triangles, the ratios of corresponding sides are equal. Let's assume the triangles are similar. If \(\frac{x}{8}=\frac{7}{4}\) (corresponding sides).
Step4: Solve the proportion for \(x\) (for part b)
Cross - multiply: \(4x = 8\times7\). Then \(4x = 56\), and \(x=\frac{56}{4}=14\).
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a. \(x = 4\)
b. \(x = 14\)