Question

find the value of the expression (t^{3}\times(2^{3}\times u)) for (t = - 1) and (u = 2).

Explanation:

Step1: Calculate $2^3$

$2^3=2\times2\times2 = 8$

Step2: Substitute $t=-1$ and $u = 2$ into the expression

The original expression $t^{3}\times(2^{3}\times u)$ becomes $(-1)^{3}\times(8\times2)$

Step3: Calculate $(-1)^{3}$ and $8\times2$

$(-1)^{3}=-1$ and $8\times2 = 16$

Step4: Calculate the final result

$(-1)\times16=-16$

Answer:

$-16$