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find uv. triangle image with right angle at w, uw = 5.4, angle at v is …

Question

find uv.
triangle image with right angle at w, uw = 5.4, angle at v is 38°
write your answer as an integer or as a decimal rounded to the nearest tenth.
uv =
submit

Explanation:

Step1: Identify trigonometric ratio

In right triangle \( \triangle UVW \), \( \angle V = 38^\circ \), \( UW = 5.4 \) (opposite to \( \angle V \)), and \( UV \) is the hypotenuse. We use the sine function: \( \sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}} \), so \( \sin(38^\circ)=\frac{UW}{UV} \).

Step2: Solve for \( UV \)

Rearrange the formula: \( UV = \frac{UW}{\sin(38^\circ)} \). Substitute \( UW = 5.4 \) and \( \sin(38^\circ)\approx0.6157 \): \( UV=\frac{5.4}{0.6157}\approx8.8 \). Rounded to nearest tenth or integer (wait, the problem says integer or decimal rounded to nearest tenth. Wait, 8.8 is closer to 9? Wait no, wait: wait, maybe I mixed up. Wait, \( \angle V = 38^\circ \), \( UW \) is opposite, \( UV \) is hypotenuse. Wait, no, wait: \( \angle W \) is right angle, so \( UW \) and \( VW \) are legs, \( UV \) is hypotenuse. Wait, \( UW = 5.4 \), \( \angle V = 38^\circ \), so \( \sin(38^\circ)=\frac{UW}{UV} \), so \( UV=\frac{5.4}{\sin(38^\circ)} \). Calculating \( \sin(38^\circ)\approx0.6157 \), so \( 5.4\div0.6157\approx8.8 \). Wait, but maybe I made a mistake. Wait, maybe \( UW \) is adjacent? No, \( \angle V \) is at \( V \), so side opposite \( \angle V \) is \( UW \), adjacent is \( VW \). So yes, sine is opposite over hypotenuse. So \( UV = \frac{5.4}{\sin(38^\circ)}\approx8.8 \). Wait, but the problem says "integer or as a decimal rounded to the nearest tenth". So 8.8, but maybe I miscalculated. Wait, let's check with calculator: \( \sin(38^\circ)\approx0.6156614753 \), \( 5.4\div0.6156614753\approx8.77 \), which rounds to 8.8 or 9? Wait, no, 8.77 is approximately 8.8 (to nearest tenth) or 9 (to integer). Wait, the problem says "integer or as a decimal rounded to the nearest tenth". Let's see, maybe the question expects using sine correctly. Wait, maybe I had the angle wrong. Wait, \( \angle V = 38^\circ \), so \( \angle U = 90 - 38 = 52^\circ \). Alternatively, using cosine: \( \cos(52^\circ)=\frac{UW}{UV} \), since \( \angle U = 52^\circ \), adjacent is \( UW \), hypotenuse \( UV \). \( \cos(52^\circ)\approx0.6157 \), same as \( \sin(38^\circ) \), so same result. So \( UV\approx8.8 \), which rounds to 9? Wait, no, 8.8 is 8.8, which is a decimal rounded to nearest tenth. Wait, maybe the problem has \( UW = 5.4 \), and we need to find \( UV \). Wait, maybe I made a mistake in the ratio. Wait, no: in right triangle, \( \sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}} \). So \( \theta = 38^\circ \), opposite is \( UW = 5.4 \), hypotenuse \( UV \). So \( UV = 5.4 / \sin(38^\circ) \approx 5.4 / 0.6157 \approx 8.8 \). So the answer is approximately 8.8, but maybe the problem expects 9? Wait, no, 8.8 is 8.8, which is a decimal rounded to nearest tenth. Wait, maybe I messed up the side. Wait, maybe \( UW \) is adjacent. Wait, no, \( \angle V \) is at \( V \), so the sides: \( V \) to \( W \) is horizontal, \( W \) to \( U \) is vertical (length 5.4), \( V \) to \( U \) is hypotenuse. So \( \angle V = 38^\circ \), so the opposite side to \( \angle V \) is \( WU = 5.4 \), so sine is correct. So \( UV = 5.4 / \sin(38^\circ) \approx 8.8 \), which is 8.8 (rounded to nearest tenth) or 9 (integer). Wait, the problem says "integer or as a decimal rounded to the nearest tenth". So 8.8 is acceptable, but maybe the system expects 9? Wait, no, let's recalculate: 5.4 divided by 0.6157 is approximately 8.77, which is 8.8 when rounded to nearest tenth. So the answer is 8.8, but maybe the problem has a typo, or I misread the side. Wait, maybe \( UW \) is 5.4, and we need to find \( UV \), so 8.8, which is 8.8. But let's c…

Answer:

8.8