Question

find the square. simplify your answer.
(3s + 3)²

Explanation:

Step1: Recall the square of a binomial formula

The formula for \((a + b)^2\) is \(a^2 + 2ab + b^2\). Here, \(a = 3s\) and \(b = 3\).

Step2: Calculate \(a^2\)

\(a^2=(3s)^2 = 9s^2\) (using the power of a product rule: \((ab)^n=a^n b^n\), so \((3s)^2 = 3^2\times s^2=9s^2\))

Step3: Calculate \(2ab\)

\(2ab = 2\times(3s)\times(3)=18s\) (multiplying the coefficients and the variable)

Step4: Calculate \(b^2\)

\(b^2 = 3^2=9\)

Step5: Combine the terms

\((3s + 3)^2=a^2+2ab + b^2=9s^2+18s + 9\)

Answer:

\(9s^2 + 18s + 9\)