Question

find the slope of each line in the figure. slope of p = slope of q = slope of r = slope of m = slope of n =

Explanation:

Step1: Recall slope formula

The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.

Step2: Find slope of line $p$

Let $(x_1,y_1)=(-4,8)$ and $(x_2,y_2)=(0, - 3)$. Then $m_p=\frac{-3 - 8}{0-(-4)}=\frac{-11}{4}=-\frac{11}{4}$.

Step3: Find slope of line $q$

Let $(x_1,y_1)=(0,6.2)$ and $(x_2,y_2)=(6.8,13)$. Then $m_q=\frac{13 - 6.2}{6.8-0}=\frac{6.8}{6.8}=1$.

Step4: Find slope of line $r$

Let $(x_1,y_1)=(0,-3)$ and $(x_2,y_2)=(12,0)$. Then $m_r=\frac{0 - (-3)}{12-0}=\frac{3}{12}=\frac{1}{4}$.

Step5: Find slope of line $m$

Let $(x_1,y_1)=(-15.5,0)$ and $(x_2,y_2)=(0,6.2)$. Then $m_m=\frac{6.2 - 0}{0-(-15.5)}=\frac{6.2}{15.5}=\frac{2}{5}$.

Step6: Find slope of line $n$

Let $(x_1,y_1)=(-5,-6.8)$ and $(x_2,y_2)=(4,-12)$. Then $m_n=\frac{-12-(-6.8)}{4 - (-5)}=\frac{-12 + 6.8}{4 + 5}=\frac{-5.2}{9}=-\frac{13}{22.5}=-\frac{26}{45}$.

Answer:

Slope of $p=-\frac{11}{4}$
Slope of $q = 1$
Slope of $r=\frac{1}{4}$
Slope of $m=\frac{2}{5}$
Slope of $n=-\frac{26}{45}$