find the quotient.

\\frac{10x^2 - 6x + 8}{-2}\

\?x^2 + x + \

Question

find the quotient.

\\frac{10x^2 - 6x + 8}{-2}\

\?x^2 +  x +  \

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Polynomial Division by Monomial" ], "new_concepts": [], "current_concepts": [ "Polynomial Division by Monomial" ] } ## Divide each term by the denominator $$ \frac{10x^2 - 6x + 8}{-2} = \frac{10x^2}{-2} + \frac{-6x}{-2} + \frac{8}{-2} $$ ## Simplify each individual term $$ \begin{aligned} \frac{10x^2}{-2} &= -5x^2 \ \frac{-6x}{-2} &= 3x \ \frac{8}{-2} &= -4 \end{aligned} $$ ## Combine the simplified terms $$ -5x^2 + 3x + (-4) = -5x^2 + 3x - 4 $$ Find the quotient. $$\frac{10x^2 - 6x + 8}{-2}$$ $-5$$x^2 +$ $3$$x +$ $-4$ { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Polynomial Division by Monomial" ] }

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Divide each term by the denominator

Simplify each individual term

Combine the simplified terms

Answer: