Question

find the product. (2x + 8)(5x + 1) 10x² + 40x + 8 7x² + 2x + 9 10x² + 42x + 8 7x² + 42x + 8

Explanation:

Step1: Apply distributive property (FOIL)

Multiply each term in the first binomial by each term in the second binomial:
$(2x + 8)(5x + 1) = 2x \cdot 5x + 2x \cdot 1 + 8 \cdot 5x + 8 \cdot 1$

Step2: Simplify each product

Calculate each term:
$2x \cdot 5x = 10x^2$, $2x \cdot 1 = 2x$, $8 \cdot 5x = 40x$, $8 \cdot 1 = 8$

Step3: Combine like terms

Add the linear terms ($2x + 40x$):
$10x^2 + (2x + 40x) + 8 = 10x^2 + 42x + 8$

Answer:

$10x^2 + 42x + 8$ (corresponding to the option "10x² + 42x + 8")