Question

find the product.
$y^2(4y^2 + y - 6)$

Explanation:

Step1: Distribute \( y^2 \) to \( 4y^2 \)

\( y^2 \times 4y^2 = 4y^{2 + 2} = 4y^4 \)

Step2: Distribute \( y^2 \) to \( y \)

\( y^2 \times y = y^{2 + 1} = y^3 \)

Step3: Distribute \( y^2 \) to \( -6 \)

\( y^2 \times (-6) = -6y^2 \)

Step4: Combine the terms

\( 4y^4 + y^3 - 6y^2 \)

Answer:

\( 4y^4 + y^3 - 6y^2 \)