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find the perimeter of $\\triangle xyz$. round your answer to the neares…

Question

find the perimeter of $\triangle xyz$. round your answer to the nearest tenth if necessary. figures are not necessarily drawn to scale.

two triangles, left triangle labeled w, v, u with angles at w: 60°, at v: 63°, sides wv=43, vu=45, uw=46; right triangle labeled x, y, z with angles at y: 63°, at x: 57°, sides yz=34.4, xy=36, zx=x

Explanation:

Step1: Check Triangle Similarity

First, we check if \(\triangle VWU\) and \(\triangle XYZ\) are similar. Let's find the angles of \(\triangle VWU\). The sum of angles in a triangle is \(180^\circ\). So, \(\angle U = 180^\circ - 60^\circ - 63^\circ = 57^\circ\). In \(\triangle XYZ\), the angles are \(63^\circ\) (at \(Y\)), \(57^\circ\) (at \(X\)), so the third angle \(\angle Z = 180^\circ - 63^\circ - 57^\circ = 60^\circ\). So, \(\triangle VWU \sim \triangle XYZ\) by AA similarity (since corresponding angles are equal: \(60^\circ\), \(63^\circ\), \(57^\circ\)).

Step2: Determine Corresponding Sides

Now, we need to find the corresponding sides. In \(\triangle VWU\), sides: \(VW = 43\), \(WU = 46\), \(VU = 45\). In \(\triangle XYZ\), sides: \(YZ = 34.4\), \(XY = 36\), \(XZ = x\). Let's find the ratio of similarity. Let's match the angles: \(\angle V = 63^\circ\) corresponds to \(\angle Y = 63^\circ\), \(\angle W = 60^\circ\) corresponds to \(\angle Z = 60^\circ\), \(\angle U = 57^\circ\) corresponds to \(\angle X = 57^\circ\). So, side \(VU\) (opposite \(\angle W = 60^\circ\)) in \(\triangle VWU\) is \(45\), and side \(YZ\) (opposite \(\angle X = 57^\circ\))? Wait, maybe better to match sides by angle correspondence. Wait, \(\angle V = 63^\circ\) (side \(WU = 46\) opposite), \(\angle Y = 63^\circ\) (side \(XZ = x\) opposite). \(\angle W = 60^\circ\) (side \(VU = 45\) opposite), \(\angle Z = 60^\circ\) (side \(XY = 36\) opposite). \(\angle U = 57^\circ\) (side \(VW = 43\) opposite), \(\angle X = 57^\circ\) (side \(YZ = 34.4\) opposite). Let's check the ratio. Let's take the side opposite \(57^\circ\): in \(\triangle VWU\), side opposite \(57^\circ\) (which is \(\angle U\)) is \(VW = 43\). In \(\triangle XYZ\), side opposite \(57^\circ\) (which is \(\angle X\)) is \(YZ = 34.4\). So the ratio of similarity \(k = \frac{34.4}{43} = 0.8\).

Step3: Find Other Sides of \(\triangle XYZ\)

Now, find \(x\) (which is \(XZ\), opposite \(\angle Y = 63^\circ\)). In \(\triangle VWU\), the side opposite \(\angle Y = 63^\circ\) (which is \(\angle V = 63^\circ\)) is \(WU = 46\). So, using the similarity ratio \(k = 0.8\), we have \(x = 46 \times k = 46 \times 0.8 = 36.8\)? Wait, no, wait. Wait, the side \(YZ = 34.4\) corresponds to which side in \(\triangle VWU\)? Let's see, \(\angle U = 57^\circ\), side \(VW = 43\) (opposite \(\angle U\)). \(\angle X = 57^\circ\), side \(YZ = 34.4\) (opposite \(\angle X\)). So the ratio is \(\frac{YZ}{VW} = \frac{34.4}{43} = 0.8\). So that's the scale factor. Now, side \(XY = 36\) in \(\triangle XYZ\) corresponds to which side in \(\triangle VWU\)? \(\angle Z = 60^\circ\), side \(XY = 36\) (opposite \(\angle Z\)). In \(\triangle VWU\), \(\angle W = 60^\circ\), side \(VU = 45\) (opposite \(\angle W\)). Let's check the ratio: \(\frac{XY}{VU} = \frac{36}{45} = 0.8\), which matches the previous ratio. Good, so the scale factor is \(0.8\). Now, side \(XZ = x\) in \(\triangle XYZ\) corresponds to side \(WU = 46\) in \(\triangle VWU\) (since \(\angle Y = 63^\circ\) in \(\triangle XYZ\) corresponds to \(\angle V = 63^\circ\) in \(\triangle VWU\), and side opposite \(\angle V\) is \(WU = 46\), side opposite \(\angle Y\) is \(XZ = x\)). So, \(x = 46 \times 0.8 = 36.8\)? Wait, no, wait: if the scale factor is from \(\triangle VWU\) to \(\triangle XYZ\), then \(XYZ\) is smaller, so \(x = 46 \times 0.8 = 36.8\)? Wait, but let's check with another side. Wait, \(YZ = 34.4\) is corresponding to \(VW = 43\), since \(\angle U = 57^\circ\) (side \(VW = 43\) opposite) and \(\angle X = 57^\circ\) (side \(YZ = 34.4\) opposite). So, \(…

Answer:

The perimeter of \(\triangle XYZ\) is \(\boxed{107.2}\).