Question

find the perimeter of the figure below, composed of an isoceles trapezoid and one semicircle. rounded to the nearest tenths place

Explanation:

Step1: Calculate the length of the semicircle arc

The formula for the circumference of a full - circle is \(C = \pi d\). For a semicircle, the length of the arc \(l=\frac{1}{2}\pi d\). Given \(d = 2\), then \(l=\frac{1}{2}\times\pi\times2=\pi\approx3.14\)

Step2: Calculate the sum of the non - arc sides of the figure

The non - arc sides are \(16\), \(4\), and \(4\). Their sum is \(16 + 4+4=24\)

Step3: Calculate the perimeter of the figure

The perimeter \(P\) of the figure is the sum of the non - arc sides and the length of the semicircle arc. So \(P=24 + 3.14=27.14\approx27.1\)

Answer:

\(27.1\)