Question

find the perimeter of the figure below, composed of an isoceles trapezoid and one semicircle. rounded to the nearest tenths place

Explanation:

Step1: Calculate the length of the semicircle arc

The formula for the circumference of a full - circle is \( C = \pi d \). For a semicircle, the length of the arc \( l=\frac{1}{2}\pi d \). Given \( d = 12 \), then \( l=\frac{1}{2}\times\pi\times12=6\pi\approx 6\times3.14 = 18.84 \).

Step2: Sum up the relevant sides of the trapezoid and the semicircle arc

The perimeter of the composite figure consists of two sides of length \( 14 \), one side of length \( 15 \), and the semicircle arc.
The sum is \( P=14 + 14+15+18.84 \).
\( P=14\times2 + 15+18.84 \).
\( P = 28+15 + 18.84 \).
\( P=61.84\approx61.7 \) (rounded to the nearest tenths).

Answer:

\( 61.7 \)