Question

find the missing side length in the triangle shown.
$y = 2\sqrt{5}$
$y = 40\sqrt{5}$
$y = 10\sqrt{2}$
$y = 200$

Explanation:

Step1: Apply Pythagorean theorem

$y^2 = 10^2 + 10^2$

Step2: Calculate sum of squares

$y^2 = 100 + 100 = 200$

Step3: Solve for y

$y = \sqrt{200} = 10\sqrt{2}$

Answer:

C. $y = 10\sqrt{2}$