Question

find the missing number so that the equation has no solutions.
□x + 11 = 2x + 4 + 3x

Explanation:

Step1: Simplify the right - hand side

First, we combine like terms on the right - hand side of the equation. The right - hand side is \(2x + 4+3x\). Combining the \(x\) terms, we have \(2x+3x = 5x\), so the equation becomes \(\square x+11 = 5x + 4\).

Step2: Analyze the condition for no solution

For a linear equation of the form \(ax + b=cx + d\) to have no solutions, the coefficients of \(x\) must be equal (\(a = c\)) and the constant terms must be different (\(b
eq d\)).
In our equation \(\square x+11 = 5x + 4\), if we want no solutions, the coefficient of \(x\) on the left - hand side (\(\square\)) must be equal to the coefficient of \(x\) on the right - hand side (which is 5), and the constant term on the left (11) is not equal to the constant term on the right (4) (which is already true since \(11
eq4\)).

Answer:

5