QUESTION IMAGE
Question
find the missing angle for each irregular polygon.
sum of the interior angles = \boxed{}^\circ
x = \boxed{}
m\angle p = \boxed{}^\circ
m\angle r = \boxed{}^\circ
m\angle t = \boxed{}^\circ
Step1: Find the sum of interior angles
The polygon is a hexagon (6 sides). The formula for the sum of interior angles of a polygon is \((n - 2)\times180^{\circ}\), where \(n\) is the number of sides. For \(n = 6\), we have \((6 - 2)\times180^{\circ}=4\times180^{\circ} = 720^{\circ}\).
Step2: Set up the equation for the sum of angles
The angles are \(115^{\circ}\), \(x + 75^{\circ}\), \(130^{\circ}\), \(x + 50^{\circ}\), \(135^{\circ}\), and \(x + 80^{\circ}\). Their sum should be \(720^{\circ}\). So:
Simplify the left - hand side:
Step3: Solve for \(x\)
Subtract 585 from both sides:
Divide both sides by 3:
Step4: Find \(m\angle P\)
\(m\angle P=x + 80^{\circ}\). Substitute \(x = 45\):
Step5: Find \(m\angle R\)
\(m\angle R=x + 75^{\circ}\). Substitute \(x = 45\):
Step6: Find \(m\angle T\)
\(m\angle T=x + 50^{\circ}\). Substitute \(x = 45\):
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Sum of the Interior Angles = \(\boldsymbol{720}\)°
\(x=\boldsymbol{45}\)
\(m\angle P=\boldsymbol{125}\)°
\(m\angle R=\boldsymbol{120}\)°
\(m\angle T=\boldsymbol{95}\)°