Question

find the measure of arc \\( \overparen{cd} \\) in \\( \odot p \\).

\\( m \overparen{cd}=\square^{\circ} \\)
(simplify your answer.)

Explanation:

Step1: Recall the total degrees in a circle

A circle has \(360^{\circ}\).

Step2: Subtract the known angles

We know one angle is \(125^{\circ}\) and another is \(90^{\circ}\) (the right - angle). Let \(m\overarc{CD}=x\). Then \(125 + 90+x=360\).

$$x = 360-(125 + 90)$$

$$x=360 - 215$$

Answer:

\(145\)