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find the length of side x to the nearest tenth. (there is a right trian…

Question

find the length of side x to the nearest tenth.
(there is a right triangle in the picture, with one leg length x, the other leg length x, and the hypotenuse length \\(\sqrt{6}\\).)
answer attempt 1 out of 2
x =
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Explanation:

Step1: Identify triangle type and sides

This is an isosceles right triangle: legs = $x$, hypotenuse = $\sqrt{6}$.

Step2: Apply Pythagorean theorem

$$x^2 + x^2 = (\sqrt{6})^2$$

Step3: Simplify the equation

$$2x^2 = 6$$
$$x^2 = 3$$

Step4: Solve for x and round

$$x = \sqrt{3} \approx 1.7$$

Answer:

1.7