QUESTION IMAGE
Question
find each measure:
- fg
- tu
1. Solving for \(x\) and \(FG\) in the first triangle:
Step1: Set up the equation for \(x\)
Since \(EF = ED = 13\), by the Angle - Bisector Theorem (in a triangle, if a ray bisects an angle of the triangle and is perpendicular to the opposite side, then it bisects the opposite side). So \(FG=GD\), which gives \(5x - 17=3x + 1\).
Subtract \(3x\) from both sides: \(5x-3x - 17=3x - 3x+1\), so \(2x-17 = 1\).
Add \(17\) to both sides: \(2x-17 + 17=1 + 17\), then \(2x=18\).
Divide both sides by \(2\): \(x=\frac{18}{2}=9\).
Step2: Calculate \(FG\)
Substitute \(x = 9\) into the expression for \(FG\) (\(FG = 5x-17\)).
\(FG=5\times9-17=45 - 17=28\).
2. Solving for \(x\) and \(TU\) in the second triangle:
Step1: Set up the equation for \(x\)
Since \(ST = SR\) (marked as equal) and \(SU\perp TR\), by the property of isosceles triangles (the altitude from the vertex of an isosceles triangle to the base bisects the base). So \(TU = UR\), which gives \(2x + 24=5x-30\).
Subtract \(2x\) from both sides: \(2x-2x + 24=5x-2x-30\), so \(24 = 3x-30\).
Add \(30\) to both sides: \(24 + 30=3x-30 + 30\), then \(54=3x\).
Divide both sides by \(3\): \(x=\frac{54}{3}=18\).
Step2: Calculate \(TU\)
Substitute \(x = 18\) into the expression for \(TU\) (\(TU = 2x + 24\)).
\(TU=2\times18+24=36 + 24=60\).
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- \(FG = 28\)
- \(TU = 60\)