find the distance, d, of $ \overline { a b } $.
$ a = ( - 7,9 ) \quad b = ( - 5,3 ) $
$ d = \sqrt { ( x _ { 2 } - x _ { 1 } ) ^ { 2 } + ( y _ { 2 } - y _ { 1 } ) ^ { 2 } } $
round to the nearest tenth.

Question

Accepted Answer

# Answer:
$6.3$
# Explanation:
## Step1: Identify coordinates
Let $A(-7,9)$ be $(x_1,y_1)$ and $B(-5,3)$ be $(x_2,y_2)$.
## Step2: Substitute into distance formula
$$
\begin{align*}
d&=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\
&=\sqrt{(-5-(-7))^2+(3 - 9)^2}\
&=\sqrt{(2)^2+(-6)^2}\
\end{align*}
$$
## Step3: Simplify the expression
$$
\begin{align*}
d&=\sqrt{4 + 36}\
&=\sqrt{40}\
&\approx6.3
\end{align*}
$$

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QUESTION IMAGE

Question

Explanation:

Step1: Identify coordinates

Step2: Substitute into distance formula

Step3: Simplify the expression

Answer: