find the distance between two points on a cartesian plane (-1,4), (3,-2)

Question

Accepted Answer

# Explanation:
## Step1: Identify the coordinates
Let $(x_1,y_1)=(-1,4)$ and $(x_2,y_2)=(3,-2)$
## Step2: Use the distance formula
The distance formula is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$
Substitute the values:
$$
\begin{align*}
d&=\sqrt{(3-(-1))^2+(-2 - 4)^2}\
&=\sqrt{(3 + 1)^2+(-6)^2}\
&=\sqrt{4^2+(-6)^2}\
&=\sqrt{16 + 36}\
&=\sqrt{52}\
&=\sqrt{4\times13}\
&=2\sqrt{13}
\end{align*}
$$

# Answer:
$2\sqrt{13}$

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QUESTION IMAGE

Question

Explanation:

Step1: Identify the coordinates

Step2: Use the distance formula

Answer: