find the distance, d, of $ \overline { a b } $.
$ a = ( 3,7 ) \quad b = ( 7,11 ) $
$ d = $
$ d = \sqrt { ( x _ { 2 } - x _ { 1 } ) ^ { 2 } + ( y _ { 2 } - y _ { 1 } ) ^ { 2 } } $
round to the nearest tenth

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Accepted Answer

# Explanation:
## Step1: Identify coordinates
Let $A=(x_1,y_1)=(3,7)$ and $B=(x_2,y_2)=(7,11)$
## Step2: Substitute into distance formula
$$
\begin{align*}
d&=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\
&=\sqrt{(7 - 3)^2+(11 - 7)^2}\
&=\sqrt{4^2+4^2}\
&=\sqrt{16 + 16}\
&=\sqrt{32}\
&\approx5.7
\end{align*}
$$

# Answer:
$d\approx5.7$

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Question

Explanation:

Step1: Identify coordinates

Step2: Substitute into distance formula

Answer: