Question

find the dimensions of a rectangle with a perimeter of 72 cm if the length is 4 cm less than three times the width. length width cm cm resources read it watch it

Explanation:

Step1: Set up variables

Let the width of the rectangle be \( w \) cm. Then the length \( l=(3w - 4) \) cm.

Step2: Use the perimeter formula

The perimeter formula of a rectangle is \( P = 2(l + w) \). Given \( P=72 \) cm. Substitute \( l=(3w - 4) \) into the formula: \( 72=2((3w - 4)+w) \).
Simplify the equation:

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Add 8 to both sides: \( 72 + 8=8w-8 + 8 \), so \( 80 = 8w \).
Divide both sides by 8: \( w=\frac{80}{8}=10 \) cm.

Step3: Find the length

Substitute \( w = 10 \) into \( l=(3w - 4) \). Then \( l=3\times10-4=26 \) cm.

Answer:

width: \( 10 \) cm, length: \( 26 \) cm