Question

find m∠bfc. m∠bfc = \\(\square^\circ\\)

Explanation:

Step1: Identify right angle and given angle

We see that \( \angle AFG \) is a right angle (\( 90^\circ \)), and \( \angle DFE = 28^\circ \). Since \( \angle BFC \), \( \angle AFB \), and the right angle relate, and \( \angle BFC + \angle DFE= 90^\circ \) (because of vertical angles and right angle properties).

Step2: Calculate \( m\angle BFC \)

Using the equation \( m\angle BFC + 28^\circ= 90^\circ \), we solve for \( m\angle BFC \) by subtracting \( 28^\circ \) from \( 90^\circ \). So \( m\angle BFC = 90^\circ - 28^\circ = 62^\circ \).

Answer:

62