Question

find the area of this trapezoid.
5 cm
6 cm
9 cm
area of a
trapezoid
$a = \frac { 1 } { 2 } h ( b _ { 1 } + b _ { 2 } )$
$a = \square \mathrm { cm } ^ { 2 }$

Explanation:

Step1: Identify the values of \(b_1\), \(b_2\), and \(h\)

From the trapezoid, \(b_1 = 5\) cm, \(b_2=9\) cm, \(h = 6\) cm.

Step2: Substitute into the area formula

The formula for the area of a trapezoid is \(A=\frac{1}{2}h(b_1 + b_2)\). Substitute the values:

$$
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Step3: Calculate the result

\(3\times14 = 42\)

Answer:

\(42\)