Question

find the area. round to the nearest tenth. 6 in. 5 in. 9 in. 11\frac{3}{4} in. enter the correct number in the box. in²

Explanation:

Step1: Calculate area of first rectangle

The first rectangle has length $l_1 = 6$ in and width $w_1=11\frac{3}{4}=\frac{4\times11 + 3}{4}=\frac{47}{4}$ in. The area formula for a rectangle is $A = l\times w$. So $A_1=6\times\frac{47}{4}=\frac{282}{4}=70.5$ in².

Step2: Calculate area of second rectangle

The second rectangle has length $l_2 = 9$ in and width $w_2=(11\frac{3}{4}- 5)=\frac{47}{4}-5=\frac{47 - 20}{4}=\frac{27}{4}$ in. The area $A_2 = 9\times\frac{27}{4}=\frac{243}{4}=60.75$ in².

Step3: Calculate total area

The total area $A=A_1 + A_2$. So $A=70.5+60.75 = 131.25\approx131.3$ in².

Answer:

$131.3$