Question

find the area of the figure. use 3.14 for \\(\pi\\). the area of the figure is about \\(\square\\) \\(\text{m}^2\\).

Explanation:

Step1: Calculate area of square

The figure has a square with side \( 12 \, \text{m} \). Area of square is \( \text{side}^2 \).
\( 12 \times 12 = 144 \, \text{m}^2 \)

Step2: Calculate area of semicircle

The diameter of the semicircle is \( 12 \, \text{m} \), so radius \( r = \frac{12}{2} = 6 \, \text{m} \). Area of semicircle is \( \frac{1}{2} \pi r^2 \). Using \( \pi = 3.14 \):
\( \frac{1}{2} \times 3.14 \times 6^2 = \frac{1}{2} \times 3.14 \times 36 = 56.52 \, \text{m}^2 \)

Step3: Total area of figure

Add area of square and semicircle.
\( 144 + 56.52 = 200.52 \, \text{m}^2 \)

Answer:

\( 200.52 \)