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Question
find f(x).
f(x)=(x^6 + 5)^{-2}
f(x)=□
Step1: Apply chain - rule
Let $u = x^{6}+5$, then $y = u^{-2}$. The chain - rule states that $\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}$. First, find $\frac{dy}{du}$.
$\frac{dy}{du}=-2u^{-3}$
Step2: Find $\frac{du}{dx}$
Since $u = x^{6}+5$, then $\frac{du}{dx}=6x^{5}$
Step3: Calculate $\frac{dy}{dx}$
Substitute $u = x^{6}+5$ back into $\frac{dy}{du}$ and multiply by $\frac{du}{dx}$.
$\frac{dy}{dx}=-2(x^{6}+5)^{-3}\cdot6x^{5}$
Step4: Simplify the expression
$f^{\prime}(x)=-12x^{5}(x^{6}+5)^{-3}=-\frac{12x^{5}}{(x^{6}+5)^{3}}$
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$-\frac{12x^{5}}{(x^{6}+5)^{3}}$