find f(-1) for the piece-wise function.

\f(x) = \begin{cases} -x, & x \le 0 \\ x, & x 0 \end{cases}\

\f(-1) = ?\

Question

find f(-1) for the piece-wise function.

\f(x) = \begin{cases} -x, & x \le 0 \\ x, & x > 0 \end{cases}\

\f(-1) = ?\

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Piecewise Functions", "Function Evaluation" ], "new_concepts": [], "current_concepts": [ "Piecewise Functions", "Function Evaluation" ] } ## Identify the correct interval for the input value $$ \begin{aligned} &x = -1 \ &-1 \le 0 \end{aligned} $$ ## Evaluate the function using the corresponding piece $$ \begin{aligned} &f(x) = -x \quad \text{for } x \le 0 \ &f(-1) = -(-1) = 1 \end{aligned} $$ Find $f(-1)$ for the piece-wise function. $$f(x) = \begin{cases} -x, & x \le 0 \ x, & x > 0 \end{cases}$$ $f(-1) =$ 1 { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Piecewise Functions" ] }

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QUESTION IMAGE

Question

Explanation:

Identify the correct interval for the input value

Evaluate the function using the corresponding piece

Answer: