Question

final exam - requires respondus lockdown browser + webcam
scored: dec 10 at 8:58pm
quiz instructions
question 30
factor completely by grouping. if the polynomial is prime, say so.
12wx - 6wy - 2xz + yz
options:
(6 - x)(2wx - y)
(6w + x)(2z + y)
(6wx)(2z - y)
(6w - z)(2x - y)

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(12wx - 6wy) + (-2xz + yz)$

Step2: Factor out GCF from each group

Factor out $6w$ from the first group: $6w(2x - y)$; factor out $-z$ from the second group: $-z(2x - y)$

Step3: Factor out the common binomial factor

Now, factor out $(2x - y)$ from both terms: $(6w - z)(2x - y)$

Answer:

$(6w - z)(2x - y)$ (assuming the option with this expression is one of the choices, likely the last option if formatted as $(6w - z)(2x - y)$)