Question

fill in the table using this function rule.
y=3x+3
table with x values -6, -3, 0, 3 and empty y cells

Explanation:

Step1: For \( x = -6 \)

Substitute \( x = -6 \) into \( y = 3x + 3 \).
\( y = 3\times(-6) + 3 = -18 + 3 = -15 \)

Step2: For \( x = -3 \)

Substitute \( x = -3 \) into \( y = 3x + 3 \).
\( y = 3\times(-3) + 3 = -9 + 3 = -6 \)

Step3: For \( x = 0 \)

Substitute \( x = 0 \) into \( y = 3x + 3 \).
\( y = 3\times0 + 3 = 0 + 3 = 3 \)

Step4: For \( x = 3 \)

Substitute \( x = 3 \) into \( y = 3x + 3 \).
\( y = 3\times3 + 3 = 9 + 3 = 12 \)

Answer:

When \( x = -6 \), \( y = -15 \); when \( x = -3 \), \( y = -6 \); when \( x = 0 \), \( y = 3 \); when \( x = 3 \), \( y = 12 \)

So the completed table (for \( y \) values) is: \(-15\), \(-6\), \(3\), \(12\) (corresponding to \( x = -6, -3, 0, 3 \) respectively)