Question

fill in the table using this function rule.
$y = -6x + 2$

$x$	$y$
$0$	$square$
$1$	$square$
$5$	$square$

Explanation:

Step1: Substitute x = -1 into y = -6x + 2

$y = -6\times(-1) + 2 = 6 + 2 = 8$

Step2: Substitute x = 0 into y = -6x + 2

$y = -6\times0 + 2 = 0 + 2 = 2$

Step3: Substitute x = 1 into y = -6x + 2

$y = -6\times1 + 2 = -6 + 2 = -4$

Step4: Substitute x = 5 into y = -6x + 2

$y = -6\times5 + 2 = -30 + 2 = -28$

Answer:

When \( x = -1 \), \( y = 8 \); when \( x = 0 \), \( y = 2 \); when \( x = 1 \), \( y = -4 \); when \( x = 5 \), \( y = -28 \). So the filled table (rows in order of \( x=-1,0,1,5 \)) has \( y \)-values \( 8, 2, -4, -28 \) respectively.