Question

fill in the boxes to add the expressions.
$(2n + 2.95)+(4.33n + 2.11)=(2n + \underline{\quad})+(2.95 + \underline{\quad})$
$=\underline{\quad}$
$(2n + 2.95)+(4.33n + 2.11)=(2n + \square)+(2.95 + \square)$
$=\square$
(simplify your answer. use integers or decimals for any numbers in the expression.)

Explanation:

First Part (Left Side)

Step1: Identify like terms

We have the expression \((2n + 2.95)+(4.33n + 2.11)\). Using the commutative property of addition for like terms (terms with \(n\) and constant terms), we can rewrite it as \((2n + 4.33n)+(2.95 + 2.11)\).

Step2: Fill in the boxes

For the first box (with the \(n\) term), we put \(4.33n\) (the other \(n\)-term), and for the second box (constant term), we put \(2.11\) (the other constant term). Then we simplify the expression:
First, add the \(n\)-terms: \(2n+4.33n = 6.33n\)
Then, add the constant terms: \(2.95 + 2.11=5.06\)
So the simplified expression is \(6.33n + 5.06\)

Second Part (Right Side)

Step1: Use commutative property

The expression \((2n + 2.95)+(4.33n + 2.11)\) can be rewritten using the commutative property of addition as \((2n+4.33n)+(2.95 + 2.11)\). So in the first box (with the \(n\) term) we put \(4.33n\) and in the second box (constant term) we put \(2.11\).

Answer:

(First Boxed Set - Left):
First box (with \(n\)): \(4.33n\), Second box (constant): \(2.11\), Simplified: \(6.33n + 5.06\)