Question

fill in the blank question

the removal of a blank molecule from 2-phosphoglyceric acid in reaction 9 of glycolysis produces phosphoenolpyruvic acid and also gives rise to a high-energy blank bond.

Explanation:

Identify reaction 9 of glycolysis

$$ \text{2-Phosphoglycerate (2-PG)} \xrightarrow{\text{Enolase}} \text{Phosphoenolpyruvate (PEP)} + \text{H}_2\text{O} $$

Determine the removed molecule

The dehydration reaction removes a water molecule (\(\text{H}_2\text{O}\)).

Determine the resulting bond type

The removal of water creates a high-energy phosphate bond in phosphoenolpyruvate.

Answer:

The removal of a <blank>water</blank> molecule from 2-phosphoglyceric acid in reaction 9 of glycolysis produces phosphoenolpyruvic acid and also gives rise to a high-energy <blank>phosphate</blank> bond.