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Question
in the figure, ( mangle1=(5x + 11)^{circ}, mangle2=(2x + 16)^{circ} ), and ( mangle3=(8x + 10)^{circ} ). what is ( mangle3 )?
Step1: Use the exterior angle theorem
The exterior angle theorem states that \(m\angle3=m\angle1 + m\angle2\). So, \((8x + 10)=(5x+11)+(2x + 16)\).
Step2: Simplify the equation
Simplify the right - hand side: \((5x+11)+(2x + 16)=5x+2x+11 + 16=7x+27\). The equation becomes \(8x + 10=7x+27\).
Step3: Solve for \(x\)
Subtract \(7x\) from both sides: \(8x-7x+10=7x - 7x+27\), which gives \(x+10=27\). Then subtract \(10\) from both sides: \(x=27 - 10=17\).
Step4: Find \(m\angle3\)
Substitute \(x = 17\) into \(m\angle3=(8x + 10)^{\circ}\). So, \(m\angle3=(8\times17+10)^{\circ}=(136 + 10)^{\circ}=146^{\circ}\).
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\(146\)