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factor the polynomial by grouping. $x^2 + 8x + x + 8$

Question

factor the polynomial by grouping.
$x^2 + 8x + x + 8$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(x^2 + 8x) + (x + 8)$

Step2: Factor out the GCF from each group

Factor out $x$ from the first group and $1$ from the second group: $x(x + 8) + 1(x + 8)$

Step3: Factor out the common binomial factor

Factor out $(x + 8)$ from both terms: $(x + 8)(x + 1)$

Answer:

\((x + 8)(x + 1)\)