Question

factor out the coefficient of the variable term.
the expression $\frac{3}{8}d + \frac{3}{4}$ factored is $square$.

Explanation:

Step1: Identify the coefficient of the variable term

The variable term is $\frac{3}{8}d$, so its coefficient is $\frac{3}{8}$.

Step2: Factor out $\frac{3}{8}$ from each term

First, rewrite $\frac{3}{4}$ with a denominator of 8: $\frac{3}{4}=\frac{6}{8}$.
Now, factor out $\frac{3}{8}$ from $\frac{3}{8}d+\frac{6}{8}$:
$\frac{3}{8}(d + 2)$ (because $\frac{3}{8}\times d=\frac{3}{8}d$ and $\frac{3}{8}\times2=\frac{6}{8}=\frac{3}{4}$)

Answer:

$\frac{3}{8}(d + 2)$