QUESTION IMAGE
Question
factor each expression.
- $x^2 - 4x - 45$
$(x - 9)(x + 5)$
- $x^2 - 5x - 6$
$(x + 5)(x - 6)$
- $x^2 - 17x + 72$
$(x - 9)(x - 8)$
- $x^2 - 36$
$(x - 6)(x - 8)$
- $x^2 + 7x - 8$
$(x - 1)(x + 8)$
- $x^2 - 3x - 54$
$(x - $
- $x^2 + 3x + 2$
$(x$
- $x^2 + 3x - 18$
$($
- $x^2 + 17x + 72$
- $x^2 + 10x + 24$
- $x^2 - 9x + 8$
- $x^2 + x - 42$
- $x^2 - x - 72$
- $x^2 + 2x - 63$
- $x^2 + 13x + 40$
- $x^2 - 2x - 8$
- $x^2 + x - 6$
- $x^2 - 4x + 3$
- $x^2 + 4x - 5$
- $x^2 - 2x - 35$
Step1: Factor \(x^2 - 4x - 45\)
We need two numbers that multiply to \(-45\) and add to \(-4\). The numbers are \(-9\) and \(5\) since \(-9\times5 = -45\) and \(-9 + 5=-4\). So, \(x^2 - 4x - 45=(x - 9)(x + 5)\).
Step2: Factor \(x^2 - 5x - 6\)
Find two numbers that multiply to \(-6\) and add to \(-5\). The numbers are \(1\) and \(-6\) (wait, no, \(5\) and \(-6\): \(5\times(-6)=-30\)? Wait, no, original problem is \(x^2 - 5x - 6\). Wait, correct numbers: multiply to \(-6\), add to \(-5\). So \(-6\) and \(1\): \(-6\times1=-6\), \(-6 + 1=-5\). So \(x^2 - 5x - 6=(x + 1)(x - 6)\)? Wait, the handwritten answer is \((x + 5)(x - 6)\). Let's check: \((x + 5)(x - 6)=x^2 - 6x + 5x - 30=x^2 - x - 30\), which is wrong. Wait, maybe a typo in the problem? If the problem was \(x^2 + x - 30\), then \((x + 6)(x - 5)\)? Wait, no. Wait, the user's problem: "3. \(x^2 - 5x - 6\)" (wait, the numbering: first is 1, then 3? Maybe a typo. Anyway, following the handwritten, but let's do correctly. For \(x^2 - 5x - 6\), correct factors: find \(a,b\) with \(a\times b=-6\), \(a + b=-5\). So \(a=-6\), \(b = 1\). So \((x - 6)(x + 1)\). But the handwritten is \((x + 5)(x - 6)\), which is wrong. Maybe the problem was \(x^2 + x - 30\), then \((x + 6)(x - 5)\), no. Anyway, let's take problem 11: \(x^2 - 9x + 8\).
Step3: Factor \(x^2 - 9x + 8\)
Find two numbers that multiply to \(8\) and add to \(-9\). The numbers are \(-8\) and \(-1\) since \(-8\times(-1)=8\) and \(-8+(-1)=-9\). So \(x^2 - 9x + 8=(x - 8)(x - 1)\).
Step4: Factor \(x^2 - 36\)
This is a difference of squares: \(a^2 - b^2=(a - b)(a + b)\). Here, \(a = x\), \(b = 6\), so \(x^2 - 36=(x - 6)(x + 6)\). The handwritten is \((x - 6)(x - 8)\), which is wrong.
Step5: Factor \(x^2 + 7x - 8\)
Find two numbers that multiply to \(-8\) and add to \(7\). The numbers are \(8\) and \(-1\) since \(8\times(-1)=-8\) and \(8+(-1)=7\). So \(x^2 + 7x - 8=(x + 8)(x - 1)\). The handwritten is \((x - 1)(x + 8)\), which is correct (multiplication is commutative).
Step6: Factor \(x^2 - 3x - 54\)
Find two numbers that multiply to \(-54\) and add to \(-3\). The numbers are \(-9\) and \(6\) since \(-9\times6=-54\) and \(-9 + 6=-3\). So \(x^2 - 3x - 54=(x - 9)(x + 6)\).
Step7: Factor \(x^2 + 3x + 2\)
Find two numbers that multiply to \(2\) and add to \(3\). The numbers are \(1\) and \(2\) since \(1\times2 = 2\) and \(1+2 = 3\). So \(x^2 + 3x + 2=(x + 1)(x + 2)\).
Step8: Factor \(x^2 + 3x - 18\)
Find two numbers that multiply to \(-18\) and add to \(3\). The numbers are \(6\) and \(-3\) since \(6\times(-3)=-18\) and \(6+(-3)=3\). So \(x^2 + 3x - 18=(x + 6)(x - 3)\).
Step9: Factor \(x^2 + 17x + 72\)
Find two numbers that multiply to \(72\) and add to \(17\). The numbers are \(8\) and \(9\) since \(8\times9 = 72\) and \(8+9 = 17\). So \(x^2 + 17x + 72=(x + 8)(x + 9)\).
Step10: Factor \(x^2 + 10x + 24\)
Find two numbers that multiply to \(24\) and add to \(10\). The numbers are \(4\) and \(6\) since \(4\times6 = 24\) and \(4+6 = 10\). So \(x^2 + 10x + 24=(x + 4)(x + 6)\).
Step11: Factor \(x^2 - 9x + 8\) (problem 11)
As in step 3, \((x - 8)(x - 1)\).
Step12: Factor \(x^2 + x - 42\)
Find two numbers that multiply to \(-42\) and add to \(1\). The numbers are \(7\) and \(-6\) since \(7\times(-6)=-42\) and \(7+(-6)=1\). So \(x^2 + x - 42=(x + 7)(x - 6)\).
Step13: Factor \(x^2 - x - 72\)
Find two numbers that multiply to \(-72\) and add to \(-1\). The numbers are \(-9\) and \(8\) since \(-9\times8=-72\) and \(-9 + 8=-1\). So \(x^2 - x - 72=(x - 9)(x + 8)\).
Step14: Factor \(x^2 + 2x - 63\)
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For each expression, the factored forms are:
- \((x - 9)(x + 5)\)
- (Correctly) \((x - 6)(x + 1)\) (but handwritten is wrong)
- \((x - 9)(x - 8)\) (wait, problem 3: \(x^2 - 17x + 72\). Numbers: multiply to \(72\), add to \(-17\). So \(-8\) and \(-9\): \(-8\times(-9)=72\), \(-8+(-9)=-17\). So \(x^2 - 17x + 72=(x - 8)(x - 9)\), which matches the handwritten.
- \((x - 6)(x + 6)\) (handwritten wrong)
- \((x - 1)(x + 8)\)
- \((x - 9)(x + 6)\)
- \((x + 1)(x + 2)\)
- \((x + 6)(x - 3)\)
- \((x + 8)(x + 9)\)
- \((x + 4)(x + 6)\)
- \((x - 8)(x - 1)\)
- \((x + 7)(x - 6)\)
- \((x - 9)(x + 8)\)
- \((x + 9)(x - 7)\)
- \((x + 5)(x + 8)\)
- \((x - 4)(x + 2)\)
- \((x + 3)(x - 2)\)
- \((x - 3)(x - 1)\)
- \((x + 5)(x - 1)\)
- \((x - 7)(x + 5)\)