Question

exponents and polynomials

evaluate \\(16x^0\\) if \\(x = -3\\).

the solution is

Explanation:

Substitute the variable value

Using the Variable Substitution knowledge point

$$ \text{Substitute } x = -3 \text{ into } 16x^0: $$

$$ 16(-3)^0 $$

Apply the order of operations

Using the Order of Operations knowledge point

$$ \text{Evaluate the exponent before multiplying:} $$

$$ (-3)^0 = 1 \quad (\text{since } a^0 = 1 \text{ for any } a eq 0) $$

Calculate the final product

$$ 16 \cdot 1 = 16 $$

Answer:

Evaluate \(16x^0\) if \(x = -3\).

The solution is <blank>16</blank>