QUESTION IMAGE
Question
explain why the sum of two rational numbers is closed under addition. give an example to make your case.
Define rational numbers
Using the Rational Numbers knowledge point, any rational number can be written as a fraction \(\frac{a}{b}\), where \(a\) and \(b\) are integers and \(b
eq 0\). Let our two rational numbers be:
where \(a, b, c, d\) are integers, and \(b, d
eq 0\).
Add the two numbers
Using the Closure Under Addition knowledge point, we find the sum of \(x\) and \(y\) by finding a common denominator:
Analyze the resulting sum
Since integers are closed under multiplication and addition, the numerator \(ad + bc\) is an integer. Similarly, the denominator \(bd\) is a non-zero integer because \(b
eq 0\) and \(d
eq 0\). Since the sum \(\frac{ad + bc}{bd}\) is a ratio of two integers with a non-zero denominator, it is a rational number.
Provide a concrete example
Let \(x = \frac{1}{2}\) and \(y = \frac{2}{3}\), which are both rational numbers.
Since \(7\) and \(6\) are integers and \(6
eq 0\), the sum \(\frac{7}{6}\) is also a rational number.
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A rational number is defined as any number that can be expressed in the form \(\frac{a}{b}\), where \(a\) and \(b\) are integers and \(b
eq 0\).
When adding two rational numbers, \(\frac{a}{b}\) and \(\frac{c}{d}\):
Because integers are closed under addition and multiplication, both the numerator (\(ad + bc\)) and the denominator (\(bd\)) must be integers. Since \(b
eq 0\) and \(d
eq 0\), the product \(bd
eq 0\). Therefore, the sum is a ratio of two integers with a non-zero denominator, which is by definition a rational number.
Example:
Since \(\frac{1}{2}\) and \(\frac{2}{3}\) are rational, and their sum \(\frac{7}{6}\) is also a rational number, this demonstrates closure under addition.