QUESTION IMAGE
Question
explain whether there is enough information given in the figure to prove that the triangles are congruent using sss or sas. select choice both triangles must have select choice pairs of congruent angles from the select choice , but select choice side lengths are known.
Step1: Analyze Triangle Congruence Conditions
To prove triangles congruent via SSS (Side - Side - Side) or SAS (Side - Angle - Side), we need to check the given information. SSS requires three pairs of congruent sides, and SAS requires two pairs of congruent sides and the included angle.
Looking at the figure (a rectangle with a diagonal, forming two right triangles), both triangles are right triangles. They share the hypotenuse (a common side), and the legs of the right triangles (the sides of the rectangle) are equal (opposite sides of a rectangle are congruent). Also, the right angles are congruent. But for SSS or SAS:
- For SSS: We need three pairs of congruent sides. We know the hypotenuse is common (1 pair) and the legs (2 pairs if the rectangle's sides are equal, but wait, actually in a rectangle, opposite sides are equal, so the two legs of each right triangle: one leg is a side of the rectangle, the other is also a side. Wait, no, the two triangles formed by the diagonal of a rectangle: let's denote the rectangle as \(ABCD\) with diagonal \(AC\). Then triangles \(ABC\) and \(CDA\) are right triangles (right angles at \(B\) and \(D\)). \(AB = CD\) (opposite sides of rectangle), \(BC=DA\) (opposite sides of rectangle), and \(AC = AC\) (common hypotenuse). So for SSS, we have three pairs of congruent sides. But wait, the question is about whether there is enough info. Wait, the first blank: "both triangles must have" - let's think about the angle pairs. Both are right triangles, so they have one pair of congruent angles (the right angles). But for SSS or SAS:
Wait, maybe the figure is a rectangle with a diagonal, so the two triangles are congruent by SSS (since \(AB = CD\), \(BC = DA\), \(AC=AC\)) or SAS (since \(AB = CD\), \(\angle B=\angle D = 90^{\circ}\), \(BC = DA\)). But the question's blanks:
First blank: "both triangles must have" - let's see the options (even though not fully visible, but from context). Wait, the original problem's blanks:
- "both triangles must have" - maybe "two" pairs of congruent sides? No, wait, for SAS, we need two sides and included angle. For SSS, three sides. Wait, maybe the first blank: "both triangles must have" - let's re - read the question: "Explain whether there is enough information given in the figure to prove that the triangles are congruent using SSS or SAS. Select Choice, both triangles must have Select Choice pairs of congruent angles from the Select Choice, but Select Choice side lengths are known."
Wait, maybe the correct answers are:
First blank: "Yes" (there is enough info), second blank: "two" (for SAS, we need two sides and included angle, but wait, no - in the rectangle case, the right angle is one angle, and the sides:
Wait, let's correct. The two triangles formed by the diagonal of a rectangle:
- They are right triangles (right angles are congruent - 1 pair of congruent angles).
- The legs: \(AB = CD\) and \(BC = DA\) (2 pairs of congruent sides), and the hypotenuse \(AC=AC\) (1 pair of congruent sides).
For SAS: We have two sides (\(AB = CD\), \(BC = DA\)) and the included angle (the right angle, which is congruent). Wait, no, the included angle for SAS should be between the two sides. In triangle \(ABC\), the right angle is between \(AB\) and \(BC\), and in triangle \(CDA\), the right angle is between \(CD\) and \(DA\). Since \(AB = CD\), \(BC = DA\), and \(\angle B=\angle D = 90^{\circ}\), so SAS applies (two sides and included angle). For SSS, three sides.
But the blanks:
- "both triangles must have" - "Yes" (there is enough info)
- "pairs of congruent angles fro…
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