expand the expression to a polynomial in standard form: (x + 5)(4x + 3)(x - 1)

Question

Accepted Answer

# Explanation:
## Step1: Multiply first two factors
Multiply $(x + 5)$ and $(4x + 3)$ using distributive property (FOIL method for binomials, extended for trinomial-like multiplication here).
$$
\begin{align*}
(x + 5)(4x + 3)&=x(4x + 3)+5(4x + 3)\
&=4x^2+3x + 20x+15\
&=4x^2+23x + 15
\end{align*}
$$
## Step2: Multiply result with third factor
Now multiply $(4x^2+23x + 15)$ with $(x - 1)$ using distributive property.
$$
\begin{align*}
(4x^2+23x + 15)(x - 1)&=4x^2(x - 1)+23x(x - 1)+15(x - 1)\
&=4x^3-4x^2+23x^2-23x + 15x-15\
&=4x^3+( - 4x^2+23x^2)+( - 23x + 15x)-15\
&=4x^3+19x^2-8x - 15
\end{align*}
$$
# Answer:
$4x^3 + 19x^2 - 8x - 15$

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Question

Explanation:

Step1: Multiply first two factors

Step2: Multiply result with third factor

Answer: